Biology - 2023

Complete Detailed Solutions · Previous Year Paper

Group A — Very Short Answer Type

1. (I) Discuss how the classification system has undergone several changes over a period of time.

Biological classification started with Aristotle's simple morphological division into plants and animals. Carolus Linnaeus formalized the Two-Kingdom system (Plantae and Animalia). Later, Ernst Haeckel proposed a Three-Kingdom system (adding Protista). Copeland introduced a Four-Kingdom system (adding Monera). Eventually, R.H. Whittaker proposed the widely accepted Five-Kingdom system (Monera, Protista, Fungi, Plantae, Animalia), and Carl Woese introduced the modern Three-Domain system (Archaea, Bacteria, Eukarya) based on ribosomal RNA differences.


1. (II) The process of transfer of hereditary character from one generation to another is known as...........?

Inheritance or Heredity.


1. (III) Name the Vitamins whose deficiency cause i) rickets ii) scurvy

i) Rickets is caused by a deficiency of Vitamin D.
ii) Scurvy is caused by a deficiency of Vitamin C (Ascorbic acid).


1. (IV) Define enzymes with suitable example.

Enzymes are biological catalysts (usually proteins) that significantly speed up the rate of specific chemical reactions in the cell without being consumed. Example: Amylase, which breaks down starch into sugars.


1. (V) Name the enzyme that transcribes hnRNA in eukaryotes.

RNA Polymerase II transcribes hnRNA (heterogeneous nuclear RNA), which is the precursor to mRNA.


1. (VI) How many essential amino acids are in the nature?

There are 9 essential amino acids for humans (Histidine, Isoleucine, Leucine, Lysine, Methionine, Phenylalanine, Threonine, Tryptophan, and Valine) out of the 20 standard amino acids.


1. (VII) What are imperfect fungi?

Imperfect fungi (Deuteromycetes) are fungi in which a sexual reproductive stage has not been observed; they only reproduce asexually.


1. (VIII) A sudden change in the gene which is heritable from one generation to other is known as_______________.

Mutation.


1. (IX) Why carbohydrates are generally optically active?

Carbohydrates are generally optically active because they contain one or more chiral carbon atoms (asymmetric carbons attached to four different groups), causing them to rotate the plane of polarized light.


1. (X) Name few of the enzyme secreted by pancreas?

Pancreatic enzymes include Trypsin and Chymotrypsin (for proteins), Pancreatic Amylase (for carbohydrates), and Pancreatic Lipase (for fats).


1. (XI) Diatoms are also called ‘pearls of the ocean’. Why?

Diatoms are called 'pearls of the ocean' because their cell walls are made of highly ornamented, glass-like silica (frustules), which makes them look shiny and beautiful under a microscope, and they are highly valuable as major primary producers in marine ecosystems.


1. (XII) Which of the following process is an exception of Mendel Law? (A. Mutation, B. Variation, C. Cloning, D. Linkage)

D. Linkage. Linkage violates Mendel's Law of Independent Assortment because genes located close together on the same chromosome tend to be inherited together.


Group B — Short Answer Type

2. Differentiate between aminotelic, uricotelic, ureotelic organisms.

Feature Ammonotelic Ureotelic Uricotelic
Excretory Product Ammonia Urea Uric Acid
Toxicity Highly toxic Less toxic than ammonia Least toxic
Water required for excretion Very high (requires large amounts of water to dilute) Moderate Very low (excreted as a semi-solid paste to conserve water)
Examples Bony fishes, aquatic amphibians Mammals, terrestrial amphibians Birds, reptiles, insects

3. Differentiate between Meiosis and Mitosis.

Feature Mitosis Meiosis
Purpose Growth, repair, and replacement of somatic (body) cells. Production of gametes (sperm and egg) for sexual reproduction.
Divisions One division Two consecutive divisions (Meiosis I and II)
Daughter Cells 2 diploid (2n) daughter cells, genetically identical to the parent. 4 haploid (n) daughter cells, genetically distinct from each other and the parent.
Crossing Over Does not occur. Occurs during Prophase I, increasing genetic variation.

4. Differentiate between prokaryotic and eukaryotic cell.

Feature Prokaryotic Cell Eukaryotic Cell
Nucleus No true nucleus. DNA is freely floating in a region called the nucleoid. True nucleus present, enclosed by a nuclear membrane.
Organelles Lacks membrane-bound organelles (no mitochondria, ER, or Golgi). Contains membrane-bound organelles (mitochondria, chloroplasts, ER).
Size Generally small (0.1 - 5.0 μm). Generally larger (10 - 100 μm).
DNA Structure Single circular chromosome. Multiple linear chromosomes.
Examples Bacteria and Archaea. Animals, Plants, Fungi, Protists.

5. Explain Epistasis with suitable example.

Epistasis is a type of gene interaction where the expression of one gene is masked or modified by the expression of one or more other genes. Unlike dominance, which involves interaction between alleles of the same gene, epistasis involves interaction between alleles of different genes.

Example: Coat Color in Labrador Retrievers
The coat color is determined by two genes:

  • Gene 1 determines the pigment color: B (Black) is dominant to b (Brown/Chocolate).
  • Gene 2 determines if the pigment is deposited in the hair: E (allows deposition) is dominant to e (prevents deposition).
If a dog has the homozygous recessive genotype ee, no pigment is deposited regardless of the B/b alleles. The dog will be Yellow. In this case, the 'e' gene is epistatic to the 'B/b' gene because it masks its expression.


6. In catalyzed reactions, the formation of the enzyme-substrate complex is the first step. Explain the other steps until the formation of the product.

The action of an enzyme is generally described by the Catalytic Cycle. After the Enzyme (E) binds to the Substrate (S) to form the Enzyme-Substrate (ES) complex, the following steps occur:

  1. Formation of the Transition State (ES* or EX‡): Once the ES complex is formed, the enzyme alters the chemical environment (by changing pH, applying physical strain, or aligning reacting groups). This lowers the activation energy and forces the substrate into an unstable, high-energy transition state.
  2. Formation of Enzyme-Product Complex (EP): The chemical bonds within the substrate are broken and/or newly formed. The substrate is chemically converted into the product, but it remains temporarily bound to the enzyme's active site, forming the EP complex.
  3. Release of Product (E + P): The product has a different shape and chemical affinity than the original substrate. It no longer fits well into the active site, causing the enzyme to release the product into the surrounding medium.
  4. Enzyme Recovery: The enzyme emerges from the reaction entirely unchanged. Its active site is now free and ready to bind to a new substrate molecule to repeat the cycle.

Group C — Long Answer Type

7. Give characteristics of E.coli, S. cerevisiae, D. Melanogaster as model organisms.

Model organisms are extensively studied to understand particular biological phenomena, with the expectation that discoveries made in the model will provide insight into the workings of other organisms.

1. Escherichia coli (E. coli) - The Model Prokaryote

  • Rapid Growth: It has a very short generation time (divides every 20-30 minutes under optimal conditions), allowing for quick experiments.
  • Simple Genetics: It has a single, small circular chromosome. Its entire genome was one of the first to be fully sequenced.
  • Ease of Manipulation: It is extremely easy to grow in cheap culture media and easily accepts foreign DNA (plasmids), making it the workhorse of molecular cloning and recombinant DNA technology.

2. Saccharomyces cerevisiae (Baker's Yeast) - The Model Simple Eukaryote

  • Simple Eukaryote: It is a single-celled organism but possesses eukaryotic structures (nucleus, mitochondria, ER), bridging the gap between bacteria and complex eukaryotes.
  • Fast Life Cycle: Like bacteria, it grows rapidly and is easy to cultivate.
  • Homology to Humans: Many of its fundamental cellular processes (cell cycle regulation, DNA repair) are highly conserved and similar to human processes.

3. Drosophila melanogaster (Fruit Fly) - The Model Multicellular Animal

  • Short Life Cycle: From egg to adult takes only about 10-12 days, allowing researchers to study multiple generations quickly.
  • High Fecundity: A single female can lay hundreds of eggs, providing large sample sizes for statistical genetic analysis.
  • Polytene Chromosomes: Their salivary glands contain giant polytene chromosomes, making it easy to observe chromosomal abnormalities and gene mapping under a microscope.
  • Genetic Similarities: Despite being an insect, about 75% of known human disease genes have a recognizable match in the fruit fly genome.

8. Explain the Hierarchy of DNA structure- from single stranded to double helix to nucleosomes.

The vast length of DNA must be highly compacted to fit inside the microscopic nucleus of a cell. This compaction occurs in a strict hierarchical structural organization:

1. Primary Structure (Single Stranded):

The primary structure is the linear sequence of nucleotides. Each nucleotide consists of a phosphate group, a deoxyribose sugar, and a nitrogenous base (Adenine, Thymine, Cytosine, or Guanine). They are linked together by phosphodiester bonds, forming a sugar-phosphate backbone with bases extending outward.

2. Secondary Structure (Double Helix):

Two complementary single strands of DNA wrap around each other to form a right-handed double helix (the Watson-Crick model). The strands are anti-parallel (running 5' to 3' in opposite directions). The helix is stabilized by hydrogen bonds between complementary bases: Adenine pairs with Thymine (2 H-bonds) and Guanine pairs with Cytosine (3 H-bonds).

3. Tertiary Structure (Nucleosomes and Chromatin):

To fit inside the cell, the double helix must be tightly folded.

  • Nucleosomes (The "Beads on a String"): The DNA double helix wraps around a core of eight positively charged histone proteins (an octamer of H2A, H2B, H3, and H4). This DNA-histone complex is called a nucleosome. This is the first level of compaction, forming a 10 nm fiber.
  • Solenoid / 30nm Fiber: The nucleosomes undergo further packing. Histone H1 binds to the "linker DNA" between nucleosomes, pulling them together into a coiled structure called a solenoid (or 30 nm fiber), creating dense chromatin.
  • Higher-order folding: The 30 nm fibers loop and scaffold onto non-histone proteins to form 300 nm fibers, which further condense into chromatids, ultimately forming the highly condensed Chromosomes visible during cell division.

9. How will you convey that Biology is as important a scientific discipline as Mathematics, Physics and Chemistry.

Biology is fundamentally interconnected with Mathematics, Physics, and Chemistry, and is arguably the most directly consequential scientific discipline to human survival and quality of life.

  1. Health and Medicine: Biology is the foundation of all medical sciences. Without a deep understanding of human anatomy, physiology, genetics, and microbiology, the development of vaccines, antibiotics, surgical procedures, and targeted cancer therapies would be impossible.
  2. Food Security and Agriculture: Understanding plant biology, genetics, and ecology allows us to breed high-yield, disease-resistant crops, manage soil health, and combat pests, which is critical for feeding a growing global population.
  3. Environmental Conservation: Biology provides the tools to understand ecosystems, biodiversity, and the impacts of climate change. This knowledge is essential to prevent ecological collapse, manage resources sustainably, and preserve the planet for future generations.
  4. Interdisciplinary Hub: Modern biology relies heavily on other disciplines, making it a central science. It uses Chemistry to understand metabolism and DNA (Biochemistry), Physics to understand fluid dynamics in blood or optics in the eye (Biophysics), and Mathematics/Computer Science to sequence genomes and model population dynamics (Bioinformatics and Biostatistics).
  5. Biotechnology: The application of biological processes for industrial purposes—such as using microbes to produce biofuels, clean up oil spills (bioremediation), or manufacture insulin—shows that biology is not just observational, but an applied engineering discipline.

While Physics explains the universe's rules and Chemistry explains matter, Biology explains the complex emergent property of life itself, making it uniquely essential.


10. Give characteristics of C. elegance, A. Thaliana, M. musculus as model organisms.

1. Caenorhabditis elegans (C. elegans) - The Model Nematode (Roundworm)

  • Transparency: Its body is entirely transparent, allowing researchers to track the development of every single cell in a living organism under a microscope.
  • Fixed Cell Count: Adult hermaphrodites have exactly 959 somatic cells. The exact lineage of every cell from the fertilized egg is mapped, making it the premier model for developmental biology and apoptosis (programmed cell death).
  • Simple Nervous System: It has exactly 302 neurons, and all the neural connections (the connectome) have been completely mapped.

2. Arabidopsis thaliana (A. thaliana) - The Model Plant

  • Small Genome: It has one of the smallest genomes among plants, which was the first plant genome completely sequenced.
  • Rapid Life Cycle: It grows from a seed to producing new seeds in just about 6 weeks, allowing for rapid genetic crossing.
  • Small Size: It is a small weed that can be easily cultivated in tight spaces (like petri dishes or small pots) in a lab environment.
  • High Seed Production: A single plant produces thousands of seeds, ideal for studying mutation rates.

3. Mus musculus (House Mouse) - The Model Mammal

  • Mammalian Physiology: As a mammal, its anatomy, physiology, and genetics are extremely similar to humans (over 90% of human genes have a direct counterpart in the mouse).
  • Genetic Manipulation: Mice are highly amenable to genetic engineering. We can create "knockout mice" (where specific genes are deleted) or "transgenic mice" (where human genes are inserted) to study human diseases like cancer, Alzheimer's, and diabetes in a living mammalian system.
  • Breeding: They reproduce relatively quickly for mammals (gestation is about 20 days) and have large litters.

11. Explain how competitive, uncompetitive and non-competitive inhibitors act on km and vmax.

Enzyme inhibitors are molecules that decrease enzyme activity. Their mechanisms profoundly affect enzyme kinetics, specifically the Michaelis constant (Kₘ, an indicator of substrate affinity; lower Kₘ means higher affinity) and maximum velocity (Vₘₐₓ).

1. Competitive Inhibition:

  • Mechanism: The inhibitor structurally resembles the substrate and competes directly for the same active site on the free enzyme.
  • Effect on Vₘₐₓ: Unchanged. If you add a massive amount of substrate, it will outcompete the inhibitor, and the enzyme can still reach its normal maximum speed.
  • Effect on Kₘ: Increases. Because the inhibitor competes for the active site, the enzyme's apparent affinity for the substrate drops, requiring more substrate to reach half Vₘₐₓ.

2. Uncompetitive Inhibition:

  • Mechanism: The inhibitor binds only to the Enzyme-Substrate (ES) complex (not the free enzyme). It binds at an allosteric site, locking the substrate in and preventing the reaction from completing.
  • Effect on Vₘₐₓ: Decreases. Since some ES complexes are permanently locked and cannot form products, the total number of functional enzyme molecules drops, lowering the maximum speed.
  • Effect on Kₘ: Decreases. By locking the substrate to the enzyme, the inhibitor prevents the substrate from leaving, artificially making the enzyme appear to have a higher affinity for the substrate.

3. Non-Competitive Inhibition:

  • Mechanism: The inhibitor binds to an allosteric site (a site other than the active site) on both the free enzyme and the ES complex. It changes the enzyme's 3D shape, preventing it from catalyzing the reaction, even if the substrate is bound.
  • Effect on Vₘₐₓ: Decreases. The functional concentration of the enzyme is reduced because inhibited enzymes cannot convert substrate to product, no matter how much substrate is added.
  • Effect on Kₘ: Unchanged. The inhibitor does not interfere with the substrate binding to the active site; it only prevents catalysis. Therefore, the affinity (Kₘ) remains the same.